AnswersAZ-Common Core Algebra II AThe Rational Roots Theorem

The Rational Roots Theorem Answers

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3

–16–202

A
–16
B
–2
C
0
D
2
10

0±2±4 ±9±3±6 ±12

Question illustration
A
0
B
±2
C
±4
D
±9
E
Option
Option E
F
±3
G
±6
H
±12
11

No, this polynomial has complex roots.No, this polynomial has irrational roots.No, this polynomial has irrational and complex roots.Yes.

A
No, this polynomial has complex roots.
B
No, this polynomial has irrational roots.
C
No, this polynomial has irrational and complex roots.
D
Yes.
12

–10 –7–531524

A
–10
B
–7
C
–5
D
3
E
15
F
24
13

Find all real solutions of this equation to answer the question.(6 – 2x)(3 – 2x)x = 40

A
Yes. Because is a root, you can cut squares with sides of in. to make the box
Option A
B
No. This equation has no real solutions.
Option B
C
No. The only real solution is x = 4. It is not possible to cut squares of this size.
Option C
14

Yuri thinks that is a root of the following function.q(x) = 6x3 + 19x2 – 15x – 28Explain to Yuri why cannot be a root.

Answer:

According to the Rational Root Theorem, a rational root must be of the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient. Since 3 is not a factor of 28 and 4 is not a factor of 6, 3/4 does not satisfy the theorem. Substituting 3/4 into the function gives -833/32, not 0, so it is not a root.

16

No, this polynomial has complex roots.No, this polynomial has irrational roots.No, this polynomial has irrational and complex roots.Yes.

A
No, this polynomial has complex roots.
B
No, this polynomial has irrational roots.
C
No, this polynomial has irrational and complex roots.
D
Yes.
18

p(2) = [___]

Answer:

-16

19

No, this polynomial has complex roots.No, this polynomial has irrational roots.No, this polynomial has irrational and complex roots.Yes.

A
No, this polynomial has complex roots.
B
No, this polynomial has irrational roots.
C
No, this polynomial has irrational and complex roots.
D
Yes.

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