AnswersFL-1200700-Mathematics for College Algebra MISSolving Quadratic Equations: Factoring

Solving Quadratic Equations: Factoring Answers

13 verified answers2 views
3

–20 or 3✔ –12 or –5 –3 or 205 or 12

A
–20 or 3
B
–12 or –5
C
–3 or 20
D
5 or 12
4

–5–33✔ 5

A
–5
B
–3
C
3
D
5
5

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6

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10

A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two congruent right triangles with areas of 44 square inches. Which statements are true? Check all that apply.

A
The area of the rectangle is 88 square inches.
B
The equation x(x – 3) = 44 can be used to solve for the dimensions of the triangle.
C
The equation x2 – 3x – 88 = 0 can be used to solve for the length of the rectangle.
D
The triangle has a base of 11 inches and a height of 8 inches.
E
The rectangle has a width of 4 inches.
11

Percy solved the equation x2 + 7x + 12 = 12. His work is shown below. Is Percy correct? Explain.1. (x + 3)(x + 4) = 12 2. x + 3 = 12 or x + 4 = 12 3. x = 9 or x = 8

Answer:

Percy is not correct because he tried to apply the zero product property to an equation that was not set equal to 0. He should have first subtracted 12 from both sides to get the equation in standard form, x^2 + 7x = 0. Then, he could factor it as x(x + 7) = 0. The correct solutions are x = 0 and x = -7.

12

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13

What did you include in your response? Check all that apply.

A
Percy was not correct.
B
Percy did not write the equation in standard form before factoring.
C
The correct solutions are 0 and –7.
D
The equation should have first been written as x2 + 7x = 0 before factoring.
E
The solutions 8 and 9 do not make the equation true.

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