A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two congruent right triangles with areas of 44 square inches. Which statements are true? Check all that apply.

The two congruent triangles each have an area of 44 square inches, so the rectangle’s area is 44 × 2 = 88 square inches. If the length is x, the width is x − 3, so x(x − 3) = 88, or x² − 3x − 88 = 0. Factoring gives (x − 11)(x + 8) = 0, so the rectangle’s length is 11 inches and its width is 8 inches. The diagonal cut makes triangles with base 11 inches and height 8 inches; the width is not 4 inches, and the equation in B uses the wrong area.

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