AnswersFL-1200330-Algebra 2 CREvaluating Logarithmic Expressions

Evaluating Logarithmic Expressions Answers

19 verified answers2 views
4

Simplify:=

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Answer:

-3

6

Match each logarithm to its value.

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Answers:
Selection 1:D
Selection 2:C
Selection 3:B
Selection 4:A
7

Which equation(s) have x = 2 as the solution?

A
log2(5x + 6) = 4
B
logx16 = 4
C
log3(6x + 4) = 3
D
logx36 = 6
9

A student solved log4(2x – 12) = 3, as shown.Step 1: 2x – 12 = 34Step 2: 2x – 12 = 81Step 4: 2x = 93Step 5: x = 46.5 Explain the error and find the correct solution.

Answer:

The student made an error in Step 1 by incorrectly swapping the base and the exponent when converting the equation from logarithmic form to exponential form. They used 3 as the base and 4 as the exponent ($3^4 = 81$) instead of using 4 as the base and 3 as the exponent ($4^3 = 64$). Correct solution: log4(2x – 12) = 3 2x – 12 = 4^3 2x – 12 = 64 2x = 76 x = 38

11

Evaluate: log279

A
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Option A
B
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Option B
C
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Option C
D
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Option D
12

B. Logarithm is equal to .

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Answer not available
13

Which equation(s) have x = –3 as the solution?

A
log3(2x + 15) = 2
B
log5(8x + 9) = 2
C
log4(–20x + 4) = 3
D
logx81 = 4
15

Which did you include in your answer?

A
The error is in Step 1. They translated from logarithmic to exponential form incorrectly.
B
The student should have used 4 as the base and 3 as the exponent. This would result in 64, not 81, on the right side of the equation.
C
The correct answer is x = 38.
16

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17

C. Logarithm is equal to .

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Answer not available
18

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19

D. Logarithm is equal to .

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Answer not available

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