AnswersSC-TX-TSIA2-MathematicsRational Equations

Rational Equations Answers

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1
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Solve: The solution is a =

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Answer:

1/6

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How many extraneous solutions are there?✔ zeroonetwo

A
zero
B
one
C
two
3

Name the true solution(s) to the equation.

A
x = 0
B
x = 1
C
x = 8
D
x = 0, x = 1, and x = 8
E
x = 1 and x = 8
F
There are no extraneous
4

Solve and check The solution is c =

Answer:

14

5

After multiplying each side of the equation by the LCD and simplifying, the resulting equation is 3x² – 20x + 12 = 03x² – 20x – 12 = 0✔ 3x² + 20x + 12 = 03x² + 20x – 12 = 0.

A
3x² – 20x + 12 = 0
B
3x² – 20x – 12 = 0
C
3x² + 20x + 12 = 0
D
3x² + 20x – 12 = 0
6

Solve and check: 1 x + 3 = x + 10 x − 2 From least to greatest, the solutions are x = and x = .

Answers:
Part 1:-8
Part 2:-4
7

x = 1 is a solution.x = 0 is a solution.x = –1 is a solution.x = –6 is a solution.

A
x = 1 is a solution.
B
x = 0 is a solution.
C
x = –1 is a solution.
D
x = –6 is a solution.
8

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9

Question text not available

Answer:

No, the student is incorrect. While solving the equation algebraically results in the value 2, this value is an extraneous solution. If you substitute 2 back into the original equation, the denominators (a 2) and (a^2 4) both become zero. Since division by zero is undefined, 2 cannot be a solution, and the equation actually has no solution.

10

mc001-1.jpg

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Option D
11

What are the solutions to the equation?

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Option A
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Option C
12

Question text not available

Answer not available
13

Name the true solution(s) to the equation.

A
x = 0
B
x = 1
C
x = 8
D
x = 0, x = 1, and x = 8
E
x = 1 and x = 8
F
There are no solutions.
14

Which of the following did you include in your answer?

A
No, the student did not check the solution to the derived equation in the original equation.
B
No, a possible solution is a = –2, but it does not check in the original equation because it makes two of the denominators equal to zero.
C
No, a = –2 is an extraneous solution, and there is no solution to the original rational equation.

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