AnswersDHS Algebra 2 VSolving Equations using Properties of Logarithms

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1
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0✔ 3e3e

Answers:
ln e3 =:3
ln e2y =:2y
2
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02 + y2ye✔ 2y

A
0
B
2 + y
C
2ye
D
✔ 2y
3

Question text not available

Answers:
eln 1 =:1
eln 5x =:5x
4

05 + x5ex✔ 5x

A
0
B
5 + x
C
5ex
D
✔ 5x
5

ln 16 - ln 8

A
ln 2
B
ln 8
C
ln 128
6

Which expressions are equivalent to 2 ln a + 2 ln b - ln a? Check all that apply.

A
ln ab2 - ln a
B
ln a + 2 ln b
C
ln a2 + ln b2 - ln a
D
2 ln ab
E
ln ab2
7

ln 3x = 3 ln xln 3 - ln x✔ ln 3 + ln x

A
3 ln x
B
ln 3 - ln x
C
✔ ln 3 + ln x
8

4 ln 2 + 4 ln x4 ln 2 + ln x 8 ln x

A
4 ln 2 + 4 ln x
B
4 ln 2 + ln x
C
8 ln x
9

Solve: 4 ln x = 2 ln 25

A
x = 5
B
x = 25
C
x = 625
12

Which did you include in your solution?

A
Since 0 in ln(3x) - 0 is not a logarithm, the property of logarithms cannot be used here.
B
The difference shown cannot be written as a quotient of logarithms.
C
The step ln(x2) = ln(3x) - (0) reduces to ln(x2) = ln(3x).
D
The possible solutions are 0 and 3, with 0 being extraneous.
15

Question text not available

Answers:
ln e3 =:3
ln e2y =:2y
16

Identify the error in the student solution shown below. Find the correct answer.

Question illustration
Answer:

The student incorrectly rewrote ln(3x) - 0 as ln(3x/0), which is undefined. The correct solution is x = 3; x = 0 is extraneous.

17

ln 2 + ln 8 - ln 4

A
ln 4
B
ln 6
C
ln 64
18

= ✔ ln 2 + ln a - ln bln 2 - ln a - ln b 2 ln a - ln b

Question illustration
A
✔ ln 2 + ln a - ln b
B
ln 2 - ln a - ln b
C
2 ln a - ln b

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