Comparing Measures of Center and Variability Answers
What information did you include in your response? Check all that apply.
z =
Robin and Evelyn are playing a target game. The object of the game is to get an object as close to the center as possible. Each player’s score is the number of centimeters away from the center. Robin’s mean is 107, and Evelyn’s mean is 138. Compare the means. Explain what this comparison indicates in the context of the data. Who is winning the game? Why?
Evelyn has the greater mean. It indicates that, on average, her objects landed farther away from the center than Robin’s. This difference means that Robin is winning the game.
Find and compare the medians of the data sets. Do the medians support your conclusion that Robin is winning the game?
Robin’s median score is 107. Evelyn’s median score is 138. The medians are the same as the means, so the same conclusion would be reached that Robin is winning.
The mean of Robin’s scores was 107. Complete the chart to find the absolute distances from the mean for each of Robin’s scores.
The mean of Evelyn’s scores was 138. Complete the chart to find the distances from the mean for each of Evelyn’s scores. x = y = z =
What is the mean absolute deviation of Evelyn’s scores?
Explain what the mean absolute deviation is in general. Explain what the MAD means in the context of Robin and Evelyn’s data.
The MAD describes the average distance from a data point to the mean. It measures variability. For this data, it shows that Evelyn’s scores varied slightly more than Robin’s.
What information did you include in your response? Check all that apply.
The mean of Evelyn’s scores was 138. Complete the chart to find the distances from the mean for each of Evelyn’s scores.
What information did you consider in your response? Check all that apply.
y =
y = -1✔ 1213
z = ✔ 78911
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