AnswersIntegrated Math II FullComparing Measures of Center and Variability

Comparing Measures of Center and Variability Answers

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y =

Answer not available
3

z =

Answer not available
5

Find and compare the medians of the data sets. Do the medians support your conclusion that Robin is winning the game?

Answer:

Robin’s median score is 107. Evelyn’s median score is 138. The medians are the same as the means, so the same conclusion would be reached that Robin is winning.

6

The mean of Robin’s scores was 107. Complete the chart to find the absolute distances from the mean for each of Robin’s scores.

Answers:
The mean of Robin’s scores was 107. Complete the chart to find the absolute distances from the mean for each of Robin’s scores.:5
The mean of Robin’s scores was 107. Complete the chart to find the absolute distances from the mean for each of Robin’s scores.:0
The mean of Robin’s scores was 107. Complete the chart to find the absolute distances from the mean for each of Robin’s scores.:12
7

The mean of Evelyn’s scores was 138. Complete the chart to find the distances from the mean for each of Evelyn’s scores.

Answers:
The mean of Evelyn’s scores was 138. Complete the chart to find the distances from the mean for each of Evelyn’s scores.:13
The mean of Evelyn’s scores was 138. Complete the chart to find the distances from the mean for each of Evelyn’s scores.:1
The mean of Evelyn’s scores was 138. Complete the chart to find the distances from the mean for each of Evelyn’s scores.:7
11

Explain what the mean absolute deviation is in general. Explain what the MAD means in the context of Robin and Evelyn’s data.

Answer:

The MAD describes the average distance from a data point to the mean. It measures variability. For this data, it shows that Evelyn’s scores varied slightly more than Robin’s.

13

y = -1✔ 1213

A
-13
B
-2
C
13
D
17
14

z = ✔ 78911

A
-13
B
-2
C
13
D
17

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