A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event B be choosing a black ball first and event R be choosing a red ball second. What are the following probabilities? P(B) = P(R | B) = P(B ∩ R) = The probability that the first ball chosen is black and the second ball chosen is red is about percent.
Answer
P(B) =:
8/12
P(R | B) =:
4/11
P(B ∩ R) =:
8/33
The probability that the first ball chosen is black and the second ball chosen is red is about percent.:
24

Question

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event B be choosing a black ball first and event R be choosing a red ball second. What are the following probabilities? P(B) = P(R | B) = P(B ∩ R) = The probability that the first ball chosen is black and the second ball chosen is red is about percent.

Answer

P(B) =:

8/12

P(R | B) =:

4/11

P(B ∩ R) =:

8/33

The probability that the first ball chosen is black and the second ball chosen is red is about percent.:

24

Revolt · Accepted Answer

8/12; P(B) =: 8/12; P(R | B) =: 4/11; P(B ∩ R) =: 8/33; The probability that the first ball chosen is black and the second ball chosen is red is about percent.: 24

Conditional Probability

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