A –0.06 C charge is placed is in a uniform electric field with a strength of 200 N/C. What is the magnitude and direction of the force on the charge?

The electric force is given by F = qE. Its magnitude is |−0.06 C| × 200 N/C = 12 N. Because the charge is negative, the force points opposite the electric field, so the answer is 12 N in the opposite direction of the field.

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