What is the slope-intercept form of the equation of the line that passes through the point negative 6 comma 1 and is perpendicular to the graph of 2 x plus 3 y is equal to negative 5 ?

Rewrite 2x + 3y = −5 in slope-intercept form: y = −(2/3)x − 5/3, so its slope is −2/3. A perpendicular line has slope 3/2, the negative reciprocal. Using the point (−6, 1), write y − 1 = (3/2)(x + 6), which simplifies to y = (3/2)x + 10. This is choice A, y is equal to 3 halves x plus 10.

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