How does the value of log_2⁡100 compare with the value of the log base 6 of 20 ?

Using change of base, log₂(100) = ln(100)/ln(2) ≈ 6.64, while log₆(20) = ln(20)/ln(6) ≈ 1.67. Their ratio is about 6.64 ÷ 1.67 ≈ 4, so log₂(100) is about 4 times log₆(20). This matches the choice saying “about 4 times.”

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