Particle q1 has a positive 6 µC charge. Particle q2 has a positive 2 µC charge. They are located 0.1 meters apart. | Recall that k = 8.99 × 109 N•. | What is the force applied between q1 and q2? | In which direction does particle q2 want to go?

Use Coulomb’s law: F = k|q₁q₂|/r². Substituting the values gives F = (8.99 × 10⁹)(6 × 10⁻⁶)(2 × 10⁻⁶)/(0.1)² ≈ 10.8 N, so the correct choice is B, 10.8 N. Since both charges are positive, they repel; particle q₂ moves away from q₁.

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