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Coulomb's Law

Question 2 • 25-26 TX-Physics B-CR

Particle q1 has a positive 6 µC charge. Particle q2 has a positive 2 µC charge. They are located 0.1 meters apart. | Recall that k = 8.99 × 109 N•. | What is the force applied between q1 and q2? | In which direction does particle q2 want to go?

Answer
A
towards particle q1, in a straight line to the left
B
away from particle q1, in a straight line to the right

Explanation

Coulomb’s law gives the force magnitude: F = k|q₁q₂|/r² = (8.99 × 10⁹)(6 × 10⁻⁶)(2 × 10⁻⁶)/(0.1)² ≈ 10.8 N. Because both charges are positive, they repel; with q₂ to the right of q₁ as indicated by the choices, q₂ moves away from q₁, to the right. The correct choice is “away from particle q1, in a straight line to the right.”

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