What are the oxidation numbers of the atoms in this reaction?Check all that apply.CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

In CH4, hydrogen is usually +1, so carbon must be −4 to make the molecule’s total oxidation number zero: (−4) + 4(+1) = 0. In CO2, each oxygen is −2, so carbon is +4. Hydrogen is +1 in both CH4 and H2O; oxygen in O2 is 0, and oxygen in H2O is −2, so C and E are not correct.

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