Lab: Heredity and Punnett Squares

Question 1

Having straight hair (S) is dominant over having curly hair (s). A heterozygous parent with straight hair is crossed with a homozygous recessive parent with curly.What is the probability that the offspring will have curly hair?

Revolt · Accepted Answer

50%

Question 2

What did you include in your response? Check all that apply.

Revolt · Accepted Answer

Yes, the offspring can have curly hair.

Question 3

Throughout the reflection, make sure you have a copy of the Student Guide and your data tables. Fill in the blanks to complete the statements.

Revolt · Accepted Answer

123369; 123370

Question 4

Each square will have the same genotype of [___].

Revolt · Accepted Answer

Aa

Question 5

Question 123379

Revolt · Accepted Answer

123379

Question 6

Use these options to describe each genotype.

Revolt · Accepted Answer

Ss is an example of .: heterozygous; SS is an example of .: homozygous dominant; ss is an example of .: homozygous recessive

Question 7

Having black hair coat (A) is dominant over having chestnut hair coat (a). Two heterozygous sheep are crossed.

Revolt · Accepted Answer

123380; 123381

Question 8

If straight hair coat (S) is dominant over curly hair (s), can two horses with straight hair coat produce an offspring with curly hair? Explain your answer.

Revolt · Accepted Answer

Yes, two horses with straight hair can produce a curly-haired offspring if both parents are heterozygous (Ss). This means each parent carries one dominant allele for straight hair and one recessive allele for curly hair. If an offspring inherits the recessive allele (s) from both parents, it will have the genotype ss and will have curly hair.

Question 9

If black hair (A) is dominant over chestnut hair (a), can two sheep with chestnut hair produce an offspring with black hair? Explain your answer.

Revolt · Accepted Answer

No, two sheep with chestnut hair cannot produce an offspring with black hair. Because chestnut hair is a recessive trait, both parents must be homozygous recessive (aa). Since neither parent carries the dominant allele for black hair (A), they can only pass the chestnut allele to their offspring, resulting in 100% chestnut-haired offspring.

Lab: Heredity and Punnett Squares Answers

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