Lab: Heredity and Punnett Squares Answers
SS✔ Ssss
✔ SSSsss
SS✔ Ssss
Throughout the reflection, make sure you have a copy of the Student Guide and your data tables. Fill in the blanks to complete the statements.
AA✔ Aaaa
⇒ black
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Having black hair coat (A) is dominant over having chestnut hair coat (a). Two heterozygous sheep are crossed.
Use these options to describe each genotype.
✔ homozygous dominanthomozygous recessiveheterozygous
homozygous dominant✔ homozygous recessiveheterozygous
Having straight hair coat (S) is dominant over having curly hair coat (s). A homozygous dominant parent is crossed with a heterozygous parent. The Punnett square shows the possible genotypes of the offspring.
If straight hair coat (S) is dominant over curly hair (s), can two horses with straight hair coat produce an offspring with curly hair? Explain your answer.
Yes, two horses with straight hair can produce a curly-haired offspring if both parents are heterozygous (Ss). This means each parent carries one dominant allele for straight hair and one recessive allele for curly hair. If an offspring inherits the recessive allele (s) from both parents, it will have the genotype ss and will have curly hair.
If black hair (A) is dominant over chestnut hair (a), can two sheep with chestnut hair produce an offspring with black hair? Explain your answer.
No, two sheep with chestnut hair cannot produce an offspring with black hair. Because chestnut hair is a recessive trait, both parents must be homozygous recessive (aa). Since neither parent carries the dominant allele for black hair (A), they can only pass the chestnut allele to their offspring, resulting in 100% chestnut-haired offspring.
What did you include in your response? Check all that apply.
What did you include in your response? Check all that apply.
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