Veronika’s five test scores are 59, 80, 95, 88, and 93. If the outlier of 59 is removed, what is the mean absolute deviation of the remaining four test scores?

After removing 59, the four scores are 80, 95, 88, and 93. Their mean is (80 + 95 + 88 + 93) ÷ 4 = 89. The absolute deviations from 89 are 9, 6, 1, and 4, so the mean absolute deviation is (9 + 6 + 1 + 4) ÷ 4 = 5, choice B.

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