A charge of 8 point 4 times 10 to the negative 4 power cap c moves at an angle of 35 degrees to a magnetic field that has a field strength of 6 point 7 times 10 to the negative 3 power T If the magnetic force is 3 point 5 times 10 to the negative 2 power cap n , how fast is the charge moving?
Answer
A
1 point 3 times 10 to the negative 4 power m/s
B
1 point 1 times 10 to the 4th power m/s
C
9 point 1 times 10 to the negative 5 power m/s
D
7 point 6 times 10 cubed m/s
Explanation
Use the magnetic-force formula F = qvB sin θ and solve for speed: v = F/(qB sin θ). Substituting the values gives v = (3.5 × 10⁻²)/[(8.4 × 10⁻⁴)(6.7 × 10⁻³)sin(35°)] ≈ 1.08 × 10⁴ m/s. Thus the speed is about 1.1 × 10⁴ m/s, choice B.
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