A 650 times 10 to the negative 4 power cap f capacitor stores 24 times 10 to the negative 3 power of charge. What is the potential difference between the plates?

Use the capacitor relationship V = Q/C. Substituting the values gives V = (24 × 10⁻³ C)/(650 × 10⁻⁴ F) ≈ 0.369 V, which rounds to 0.37 V. Therefore, the potential difference is choice B, 0.37 V.

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