A sample of a compound contains 32 point 0 g cap c and 8 point 0 g cap h Its molar mass is 30 point 0 g over mol What is the compound’s molecular formula?

Convert each element’s mass to moles: 32.0 g C ÷ 12.0 g/mol = 2.67 mol C, and 8.0 g H ÷ 1.0 g/mol = 8.0 mol H. Dividing by the smaller amount gives a C:H ratio of 1:3, so the empirical formula is CH₃, with a molar mass of 15.0 g/mol. The compound’s molar mass, 30.0 g/mol, is twice that, so its molecular formula is C₂H₆, choice B.

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