What is the solution to x6 – 6x 5 + 15x 4 – 20x 3 + 15x 2 – 6x + 1 ≥ 0?

The expression matches the binomial expansion of (x − 1)⁶. Any real number raised to an even power is nonnegative, so (x − 1)⁶ ≥ 0 for every real x. Therefore, the solution is all real numbers, choice C.

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