What is the solution to x 3 + x 2 ≤ 10x – 8?

Move everything to the left: x³ + x² − 10x + 8 ≤ 0. Factoring gives (x + 4)(x − 1)(x − 2) ≤ 0, so the zeros are −4, 1, and 2. Checking the signs between these zeros shows the product is nonpositive on (−∞, −4] and [1, 2]. Thus the solution is choice D, (−∞, −4] ∪ [1, 2].

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