Consider the function f of x is equal to the fraction with numerator x squared plus 11 x minus 12 and denominator x minus 1 Which statement describes the discontinuity at x is equal to 1 ?

Factor the numerator: x² + 11x − 12 = (x + 12)(x − 1). For x ≠ 1, the factor x − 1 cancels, so f(x) = x + 12. The function therefore has a hole at x = 1, and extending it with f(1) = 1 + 12 = 13 removes the discontinuity; this is choice A.

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