Three times the square of a number is greater than a second number. The square of the second number increased by 6 is greater than the first number. Which system of inequalities represents these criteria?

Let x be the first number and y be the second number. “Three times the square” of the first number is 3x², and it is greater than the second number, so 3x² > y. The square of the second number increased by 6 is y² + 6, which is greater than the first number, so y² + 6 > x; together these are choice C.

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