A spinning top rotates so that its edge turns at a constant speed of 0 point 6 3 m/s If the top has a radius of 0 point 1 0 m , what is the centripetal acceleration of the edge of the top?

For motion in a circle, centripetal acceleration is a = v²/r. Using the edge speed of 0.63 m/s and radius of 0.10 m gives a = (0.63)² ÷ 0.10 = 3.969 m/s², which rounds to 4.0 m/s². The correct choice is 4.0 m/s².

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