A 440 kilograms roller coaster car is going 26 meters per second when it reaches the lowest point on the track. If the car started from rest at the top of a hill, how much higher was that point on the track than the lowest point? (Use g is equal to 9 point 8 0 the fraction with numerator m and denominator s squared , and ignore friction.)
With no friction, the car’s gravitational potential energy at the top becomes kinetic energy at the bottom: mgh = ½mv². The mass cancels, so h = v²/(2g) = 26²/(2 × 9.80) = 676/19.6 ≈ 34.5 m. The closest choice is 34 m.
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