A cafeteria manager can choose from among six side dishes for the lunch menu: applesauce, broccoli, corn, dumplings, egg rolls, or French fries. He uses a computer program to randomly select three dishes for Monday’s lunch. What is the theoretical probability that applesauce and broccoli will both be offered on Monday?

There are 6 possible dishes, and the program selects 3, so there are 20 possible groups of dishes: 6 choose 3 = 20. To include both applesauce and broccoli, the third dish can be any of the other 4 dishes, giving a probability of 4/20 = 1/5 = 20 percent. The correct choice is A, 20 percent.

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