Use substitution to write an equivalent quadratic equation.(3x + 2)2 + 7(3x + 2) – 8 = 0u² + 7u - 8 = 0, where u = (3x + 2)²u² + 7u - 8 = 0, where u = 3x + 2u² + 7u - 8 = 0, where u = 7(3x + 2)u² + u - 8 = 0
Rewrite the equation in terms of u. u² - 17u - 16 = 017u² + u + 16 = 0-u² + 17u + 16 = 0u² - 17u + 16 = 0
Factor. (u + 16)(u + 1) = 0(u - 16)(u - 1) = 0(u + 17)(u - 1) = 0
What are the solutions of the original equation?x = 1 or x = –2x = –1 or x = 2x = –5 or x = –2x = 4 or x = –5
Which equation is equivalent tof(x) = 16x4 – 81 = 0?(4x² - 9)(4x² - 9) = 0(4x² + 9)(4x² - 9) = 0(4x - 9)(4x - 9) = 0(4x + 9)(4x - 9) = 0
Select all of the zeroes of the function.
Solve x4 – 17x2 + 16 = 0.Let u = x17x²x²-17x².
Select all of the solutions to the original equation.
Solve (x + 3)2 + (x + 3) – 2 = 0.Let u = xx + 3(x + 3)²x²
What are the solutions of 4x4 – 4x2 = 8?
Solve the equation 6(2x + 4)2 = (2x + 4) + 2.
Solve (x + 4)2 – 3(x + 4) – 3 = 0 using substitution.u = xx + 43(x + 4)(x + 4)²
Select the solution(s) of the original equation.
Rewrite the equation in terms of u.
Factor the equation. (u + 2)(u – 1) = 0(u + 1)(u – 2) = 0(u – 2)(u – 1) = 0
Did you find these answers helpful?