Solve (x + 4)2 – 3(x + 4) – 3 = 0 using substitution.u = xx + 43(x + 4)(x + 4)²

The expression (x + 4) appears as a whole in both the squared term and the linear term. Set u = x + 4, so the equation becomes u² − 3u − 3 = 0. The correct choice is x + 4.

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