AnswersSC-TX-TSIA2-MathematicsRational Equations

Rational Equations Answers

15 verified answers
1
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Solve: The solution is a =

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Answer:

1/6

2
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How many extraneous solutions are there?✔ zeroonetwo

A
✔ zero
B
one
C
two
3

Name the extraneous solution(s) to the equation.✔ x = 0x = 1x = 8x = 0, x = 1, and x = 8x = 1 and x = 8X There are no extraneous

A
✔ x = 0
B
x = 1
C
x = 8
D
x = 0, x = 1, and x = 8
E
x = 1 and x = 8
F
X There are no extraneous
4

Solve and check The solution is c =

Question illustration
Answer:

14

5

After multiplying each side of the equation by the LCD and simplifying, the resulting equation is 3x² – 20x + 12 = 03x² – 20x – 12 = 0✔ 3x² + 20x + 12 = 03x² + 20x – 12 = 0.

A
3x² – 20x + 12 = 0
B
3x² – 20x – 12 = 0
C
✔ 3x² + 20x + 12 = 0
D
3x² + 20x – 12 = 0
6

1 x + 3

Answers:
Blank 1:-8
Blank 2:-4
7

Question text not available

Answers:
Blank 1:-8
Blank 2:-4
8

x = 1 is a solution.x = 0 is a solution.x = –1 is a solution.x = –6 is a solution.

A
x = 1 is a solution.
B
x = 0 is a solution.
C
x = –1 is a solution.
D
x = –6 is a solution.
9

Question text not available

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Option C
10

Question text not available

Answer:

No, the student is incorrect. While solving the equation algebraically results in the value -2, this value is an extraneous solution. If you substitute -2 back into the original equation, the denominators (a + 2) and (a^2 - 4) both become zero. Since division by zero is undefined, -2 cannot be a solution, and the equation actually has no solution.

11

Question text not available

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Option A
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Option C
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Option D
12

What are the solutions to the equation?

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Option A
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Option C
13

Question text not available

Answer:

-4

14

Name the true solution(s) to the equation.X x = 0x = 1x = 8x = 0, x = 1, and x = 8✔ x = 1 and x = 8There are no solutions.

Answers:
Selection 1:x = 1 and x = 8
Selection 2:x = 0
15

Which of the following did you include in your answer?

A
No, the student did not check the solution to the derived equation in the original equation.
B
No, a possible solution is a = –2, but it does not check in the original equation because it makes two of the denominators equal to zero.
C
No, a = –2 is an extraneous solution, and there is no solution to the original rational equation.

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