Solve: The solution is a =

1/6
Solve and check The solution is c =

14
What are the solutions to the equation?



After multiplying each side of the equation by the LCD and simplifying, the resulting equation is 3x² – 20x + 12 = 03x² – 20x – 12 = 0✔ 3x² + 20x + 12 = 03x² + 20x – 12 = 0.
Solve and check: 1 x + 3 = x + 10 x − 2 From least to greatest, the solutions are x = and x = .
x = 1 is a solution.x = 0 is a solution.x = –1 is a solution.x = –6 is a solution.
Name the true solution(s) to the equation. Name the extraneous solution(s) to the equation.
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No. The student is not correct. Although clearing the denominators gives the possible solution a = -2, it is invalid in the original equation because it makes two denominators equal to zero. Thus, a = -2 is extraneous, and the original equation has no solution.
Which of the following did you include in your answer?
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Question text not available
Name the extraneous solution(s) to the equation.
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