⇒ 2 x2 − 2x − 15 = 0 Potential solutions are −3 and 5 x2 − 15 = 2x x − 5 = 0 or x + 3 = 0 (x − 5)(x + 3) = 0
Answer
⇒ 2:
Given equation
Part 2:
5
Part 3:
1
Part 4:
4
Part 5:
3

Question

⇒ 2 x2 − 2x − 15 = 0 Potential solutions are −3 and 5 x2 − 15 = 2x x − 5 = 0 or x + 3 = 0 (x − 5)(x + 3) = 0

Revolt · Accepted Answer

⇒ 2: Given equation; Part 2: 5; Part 3: 1; Part 4: 4; Part 5: 3

Solving Equations using Properties of Logarithms