Find the solutions to the equation 102x + 11 = (x + 6)2 – 2. Which values are approximate solutions to the equation? Select two answers.

Rewrite the equation as 10^(2x) + 13 = (x + 6)^2. For the negative values being tested, 10^(2x) is extremely close to 0, so the approximate solutions satisfy (x + 6)^2 ≈ 13. Thus x ≈ -6 ± √13, which is about -9.6 and -2.4. The approximate solutions are –9.6 and –2.4.

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