Question 2 • FL-1200330-Algebra 2 CR
A rectangle’s perimeter is 2x + 2w, where x and w are its side lengths. Since the fencing gives a perimeter of 120 feet, 2x + 2w = 120, so the other side is w = 60 − x. The area is length times width, so y = x(60 − x), which is choice A.
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