Question 1 • FL-1200330-Algebra 2 CR
For a quadratic y = ax² + bx + c, the vertex’s x-coordinate is −b/(2a). In choice B, a = 3 and b = −6, so the vertex’s x-coordinate is −(−6)/(2·3) = 1. Substituting x = 1 gives y = 3 − 6 − 3 = −6, so choice B, y = 3x² − 6x − 3, has vertex (1, −6).
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