In triangle ABC, AB = 90 in., BC = 80 in., and angle B measures 50°. What is the approximate perimeter of the triangle?

Use the Law of Cosines to find the third side, opposite the 50° angle: AC² = 90² + 80² − 2(90)(80)cos(50°), so AC is approximately 72.4 inches. Add the three side lengths: 90 + 80 + 72.4 = 242.4 inches. The approximate perimeter is 242.4 inches, choice A.

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