Question 2 • TX-Pre-Calculus
For a quadratic y = ax² + bx + c, the vertex’s x-coordinate is −b/(2a). In choice A, this is −24/(2 × 4) = −3; substituting x = −3 gives y = 4(9) + 24(−3) + 38 = 2. So choice A, y = 4x² + 24x + 38, has a vertex at (−3, 2).
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