A charge of +0.08 C moves to the right due to a 4 N force exerted by an electric field. What is the magnitude and direction of the electric field?

Use the relationship E = F/q. The magnitude is 4 N ÷ 0.08 C = 50 N/C. Because the charge is positive, the electric field points in the same direction as the force: to the right. The correct choice is 50 N/C right.

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