What is the energy of a photon with a frequency of 2.2 × 1016 Hz? Planck’s constant is 6.63 × 10–34 J•s.

Use the photon energy formula E = hf, where h is Planck’s constant and f is the frequency. E = (6.63 × 10⁻³⁴ J•s)(2.2 × 10¹⁶ Hz) = 1.46 × 10⁻¹⁷ J, which rounds to 1.5 × 10⁻¹⁷ J, choice A.

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