If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 1030 kg, what is the average distance between the planet and the star?

Use Kepler’s third law for a planet orbiting a much more massive star: r³ = GMT²/(4π²). Substituting G = 6.67 × 10⁻¹¹, M = 6.2 × 10³⁰ kg, and T = 2.8 × 10⁸ s gives r³ ≈ 8.2 × 10³⁵ m³, so r ≈ 9.4 × 10¹¹ m. This matches choice B, 9.36 × 10¹¹ m.

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