AnswersSC-TX-TSIA2-MathematicsRational Equations

Vertical Asymptotes of Rational Functions Answers

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Which of the following represents the solution of ?

Question illustration
A
x = one-fifth
Option A
B
x = five-ninths
Option B
C
all real numbers
D
no solution
2
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Which solution to the equation is extraneous?

Question illustration
A
x = 1 and x = –4
B
neither x = 1 or x = –4
C
x = 1
D
x = –4
3

What is the solution to the equation ?

Question illustration
A
m = 3
B
m = 6
C
all real numbers
D
no solution
4

Working alone, it would take Shandra 40 minutes to sand a table. To sand the same table, also working alone, it would take Kelly 1 hour. If they work together, the situation can be modeled by the following equation, where t is the time it would take to sand the table working together.Shandra claims it will take them about 50 minutes working together, because 50 is the mean of 40 and 60. Which best describes Shandra’s claim?

Question illustration
A
Shandra’s claim is correct.
B
Shandra’s estimate is too high because she should have found the differences instead of the mean.
C
Shandra’s estimate is too high because it will take them about 24 minutes.
D
Shandra’s estimate is too low because it will take them about 100 minutes.
5

What are the solutions to the equation ?

Question illustration
A
w = –6 and w = –2
B
w = 0, w = 2, and w = 6
C
w = 0 and w =
Option C
D
w = 2 and w = 6
6

What is the solution to the equation ?

Question illustration
A
d = –4 and d = 2
B
d = –2 and d = 4
C
d = 1
D
d = 2
7

What is the solution of ?

Question illustration
A
y = –4
B
y = –2
C
y = 4
D
y = 6
8

Which solution to the equation is extraneous?

Question illustration
A
g = –4
B
g = –4 and g = 16
C
neither g = –4 nor g = 16
D
g = 16
9

What is true about the solution of ?

Question illustration
A
, and they are actual solutions.
Option A
B
, but they are extraneous solutions.
Option B
C
x = 3, and it is an actual solution.
D
x = - 3, but it is an extraneous solution.
10

What is the solution for the equation ?

Question illustration
A
b = –4 and b = 0
B
b = –4
C
b = 0 and b = 4
D
b = 4

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