AnswersPrecalculusThe General Equation of Conic Sections

Conic Inequalities Answers

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1
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Which inequality is represented by the graph?

A
y ≥ –3(x + 1)2 + 5
B
y ≤ –3(x + 1)2 + 5
C
x ≥ –3(y + 1)2 + 5
D
x ≤ –3(y + 1)2 + 5
2
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✔ y – 0y – 1y – 2

A
✔ y – 0
B
y – 1
C
y – 2
3

8✔ 948

A
8
B
✔ 9
C
48
171030

Complete the square to justify that Julia’s graph is correct.

Answers:
()2 + ()2 ≤:x + 1
()2 + ()2 ≤:y – 0
()2 + ()2 ≤:9
171031

Describe the features of x ≥ (y – 3)2 – 2? Check all that apply.parabola with a vertex (–2, 3) opening to the leftparabola with a vertex (–2, 3) opening to the rightparabola with a vertex (–2, 3) opening upquadrant 2 is not shaded at allquadrant 3 is not shaded at all

A
parabola with a vertex (–2, 3) opening to the left
B
parabola with a vertex (–2, 3) opening to the right
C
parabola with a vertex (–2, 3) opening up
D
quadrant 2 is not shaded at all
E
quadrant 3 is not shaded at all
171032

Some steps are shown in converting the following conic inequality from general form to standard form. Complete the conversion and identify the shape, key feature, and which ordered pair is part of the solution set.

Answers:
The conic represented in this inequality is a(n) .:ellipse with a dashed line boundary
The center is at .:(1, –2)
The ordered pair, , is a solution to the inequality.:(–2, 0)
171033

Showing that (9, 1) is a solution of which inequality would justify shading inside the graph of the curve.

A
x2 – y2 > 84
B
x ≥ 3(y + 2)2 – 2
C
4(x – 4)2 – 16(y + 1)2 > 36
D
64(x – 8)2 + 12y2 < 144
171035

Miranda graphed (y + 1)2 > 6(x – 2). Which could Miranda use to justify that her graph is correct? Check all that apply.Because only the y quantity is squared, the curve is a parabola.The parabola opens right because 6 is in front of the x-quantity.There is a strict inequality so the boundary is included in the solution set.The shading is outside the parabola because (0, 0) satisfies the inequality.The values subtracted from x and y in the equation are the coordinates of the vertex which is (2, –1).

A
Because only the y quantity is squared, the curve is a parabola.
B
The parabola opens right because 6 is in front of the x-quantity.
C
There is a strict inequality so the boundary is included in the solution set.
D
The shading is outside the parabola because (0, 0) satisfies the inequality.
E
The values subtracted from x and y in the equation are the coordinates of the vertex which is (2, –1).
171036

Some steps are shown in converting the following conic inequality from general form to standard form. Complete the conversion and identify the shape, key feature, and which ordered pair is part of the solution set.

Answers:
The conic represented in this inequality is a(n) .:ellipse with a dashed line boundary
The center is at .:(1, –2)
The ordered pair, , is a solution to the inequality.:(–2, 0)
171037

✔ (1, –2)(–2, 1)(–1, 2)(2, –1)

A
✔ (1, –2)
B
(–2, 1)
C
(–1, 2)
D
(2, –1)
171038

(1, 0)✔ (–2, 0)(1, –4)(0, –3)

A
(1, 0)
B
✔ (–2, 0)
C
(1, –4)
D
(0, –3)

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