Which points justify shading inside the conic inequality 8x2 – 12x + 4y2 + 4y – 20 ≤ 0? Check all that apply.(–1, –2)(–1, –1)(0, 0)(0, 2)(1, –2)

Substitute each point into the left side; a point qualifies when the result is 0 or less. For (−1, −1), the result is 20 + 0 − 20 = 0; for (0, 0), it is −20; and for (1, −2), it is −16, so all three qualify. The other points give 8 and 4, which are greater than 0, so (−1, −2) and (0, 2) do not qualify.

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