Question 171035 • Precalculus
The boundary equation, (y + 1)² = 6(x − 2), is a parabola because only y is squared. In the form (y − k)² = 4p(x − h), the positive coefficient 6 means it opens right, and its vertex is (h, k) = (2, −1). The strict inequality excludes the boundary, so C is false. Testing (0, 0) gives 1 > −12, which is true; the origin lies on the outside (left) side of this right-opening parabola, so that side is shaded.
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