Describe the features of x ≥ (y – 3)2 – 2? Check all that apply.parabola with a vertex (–2, 3) opening to the leftparabola with a vertex (–2, 3) opening to the rightparabola with a vertex (–2, 3) opening upquadrant 2 is not shaded at allquadrant 3 is not shaded at all

Rewrite the boundary as x = (y − 3)² − 2. Its vertex is (−2, 3), and because x is expressed as a squared y-term, the parabola opens to the right. The inequality x ≥ (y − 3)² − 2 shades the region on or to the right of the curve. In quadrant III, y < 0 makes (y − 3)² − 2 positive, so no negative x can satisfy the inequality; quadrant III is not shaded. The correct choices are the right-opening parabola and quadrant III not shaded.

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