What is the empirical formula for a compound if a sample contains 1 point 0 g of cap s and 1 point 5 g of cap o ?

Convert each mass to moles: 1.0 g S ÷ 32.1 g/mol ≈ 0.031 mol S, and 1.5 g O ÷ 16.0 g/mol ≈ 0.094 mol O. Divide both amounts by the smaller value to get a ratio of about 1 S to 3 O. The empirical formula is SO₃, choice D.

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